Rotate elements in an array to right k times.

Question

Rotate elements in an array to right  k times.

Ty · Accepted Answer

#define element int
element a[] = {1, 2, 3, 4, 5, 6, 7, 8, 9};

int rotate_a(int k)
{
    int i, bufsize, a_size;
    element *buf;
    a_size = sizeof(a);
    bufsize = sizeof(element) * k;
    if (!(buf = malloc(bufsize))) return -1;
    memcpy(buf, (void *)a + a_size - bufsize, bufsize);
    memmove((void *)a + bufsize, a, a_size - bufsize);
    memcpy(a, buf, bufsize);
    return 1;
}

Jorix · Answer

private static int[] flipArrayRight(int[] array, int times) {
		for (int i = 0; i  0; k--) {
				array[k] = array[k - 1];
			}
			array[0] = last;
		}
		return array;
	}

www.niisar.com · Answer

public static Array rotateArrayByNFromRight(int[] ArrayToBeRotated, int N)
        {
            int ArrayLength = ArrayToBeRotated.Length;
            if ((N > 0) && (N <= ArrayLength))
            {
                Array.Reverse(ArrayToBeRotated, 0, ArrayLength - N);
                Array.Reverse(ArrayToBeRotated, ArrayLength - N, N);
                Array.Reverse(ArrayToBeRotated);
            }
            else
            {
                Console.WriteLine("invalid");
            }
            return ArrayToBeRotated;
        }

Raviteja Ainampudi · Answer

x = [1,2,3,4,5] #Given list or array.
k = len(x)
y = 3
def rot (x,y):
    for i in range(y):
        temp = x[0]
        del x[0]
        x.insert(k-1,temp)
    print x
rot(x,y)

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