How would you implement

int atoi ( const char * str );

Question

How would you implement

int atoi ( const char * str );

Anónimo · Accepted Answer

You need to subtract the ascii value of zero to get the integer value of the char before multiplying by 10.

The Dude · Answer

#include 
#include 

unsigned int my_atoi(const char* str) {
  int num = 0;
  while (*str) {
	num *= 10;
    num += (*str++ - '0');
  }
  return num;
}

int main(int argc, char* argv[])
{
	printf("atoi(%s)=%d
",argv[1], my_atoi(argv[1]) );
	return 0;
}

Anónimo · Answer

I parsed the string from left to right, multiplying the temp int by 10 for each char traversed.

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