Write code to reverse the digits in an integer.

Question

no one · Accepted Answer

int reverse(int a) {
		int b = 0;
		while (a>0) {
			b *= 10;
			b += a%10;
			a /= 10;
		}
		return b;
	}

Anónimo · Answer

To Robert:  Remember integer division will truncate the value, so 93/10 = 9, not 9.3.

Robert Hannum · Answer

I am not sure this solution would work because if a was 93, your program would produce the answer 39.3, but I am not really a software guy so idk. my logic is that 

a=93
93%10 = 3
b=3
a=9.3
*next iteration*
b=30
9.3%10 = 9.3
b = 39.3

is this correct? just as a disclaimer, I am not trying be an jerk, I am just practicing interview questions lol

Charles Hill · Answer

function reverseNum(num) {
    let result = 0,
         isNeg = num  0) {
        result = result * 10 + num % 10;
        num = Math.floor(num / 10);
    }
    return isNeg ? -1 * result : result;
}

Charles Hill · Answer

The above formatted incorrectly.


function reverseNum(num) {
    let result = 0,
        isNeg = num  0) {
        result = result * 10 + num % 10;
        num = Math.floor(num / 10);
    }
    return isNeg ? -1 * result : result;
}

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