Pregunta de entrevista de CarltonOne Engagement
$sql = "SELECT * FROM table as a WHERE a.id ={ $id }"; What is wrong with the code ?
Respuesta de la entrevista
Anónimo
5 nov 2018
SQL Injection vulnerability with $id.
$sql = "SELECT * FROM table as a WHERE a.id ={ $id }"; What is wrong with the code ?
Anónimo
SQL Injection vulnerability with $id.