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The Emirates Group
A un Junior Network Engineer le preguntaron...3 de octubre de 2012

How long do you plan to work here?

33 respuestas

4 years

As long as possible

For ever

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Aryaka Networks

tcp and udo difference to explain on board with examples, what is ping,traceroute, 7 layer workings, vlan, subnetting

20 respuestas

Topic they asked me was distance education vs college education, they will check grammar not accent. No matter how strong your technical skills are, they will allow to 2nd round oly if you clear GD. be prepared. Best company as for fresher. I had 4 rounds- gd, face to face ( hr kind), and then 2 technical rounds. one of my friend had another technical round, totally5 rounds. So final point, they need technical strong guys...i mean it. In Interview they will ask you everythin regarding network(do read wan optimization too), check interviews question which i posted. As your ccnp certified it would be piece of cake for you. do drop mail if need any other info. three of my frnds attended that so have clear idea on interview process. all de best Menos

Nope. no sign at all. In another company interview, met another guy who attended interview at aryaka networks on the 3rd june. He told me same answer :D. you better search for another job, i did like that and got selected to another company, don't just wait for that. If you want confirm, u can ask HR through linkedin (if you remember HR name). or paste your mail id il send the HR linkedin link. Menos

did they told you that hr will contact you after 4 rounds or something else , i got interviewed too and they told me that , i need to know ,it will be really helpful for me if you could tell me what they said. thanks Menos

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Jazz

Where do you live?

14 respuestas

Lahore

rawalpindi

rawalpindi

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Meta

All questions are mentions in the review and practice following coding questions for sure on leetcode.

14 respuestas

3. convert the sentence to the modified pig-latin/goat-latin language. Complexity Time: O(n) + O(5) + O(k(k+1)/2) Considering total n characters in sentence. m characters/word O(n): Reading compelete sentence O(2): For vowel. Append ma O(3): For consonant. Append ma and 1st character 1+2+3+... k words = k(k+1)/2 Space: O(n) + 2O(m) + O(5) O(5): unordered_set of vowels 2O(m): Storing 2 word O(n): Storing complete sentence Code #include #include #include void AppendA(std::string& strWord, int& count){ int i = 0; strWord += "ma"; while(i++ us = {'a','e','i','o','u'}; //1st Letter is Vowel if (us.find(std::tolower(strParsed.at(0))) != us.end()) { strWord = strParsed; AppendA(strWord, ++count); } else //consonant { strWord = strParsed.substr(1,strParsed.size()); strWord += strParsed[0]; AppendA(strWord, ++count); } } int main(){ std::string strInput = "Adam wants to go to the university"; std::string strOutput, strWord, strParsed; int count = 0; for (auto& i:strInput){ if (i == ' '){ Process(strParsed, strWord, count); strOutput += strWord + ' '; strWord = ""; strParsed = ""; } else //Store word in strParsed { strParsed += i; } } Process(strParsed, strWord, count); strOutput += strWord ; std::cout<<"Converted string="< Menos

1. You receive a vector/ array and 2 numbers, eg 2 and 5. Between those 2 positions in the vector (2 and 5) you have to reverse the order of the elements. Code #include #include #include using vec = std::vector; using itr = std::vector::iterator; int main(){ vec v = {1,2,9,8,4,5,23,5,252,445,677,5}; //Find position of 2 itr it1 = std::find(v.begin(), v.end(), 2); //O(n) //Find position of 5 itr it2 = std::find(v.begin(), v.end(), 5); //O(n) std::reverse(it1+1, it2); //O(n) for (auto i:v) std::cout< Menos

2. Count words and output top n Complexity n: number of words Space map=O(n), priority_queue = O(k). Since we only create queue of size=k, output vector = O(k) Time Creation of map=O(n), Creation of priority Queue=O(n), Creation of output vector=O(k) Code #include #include #include #include using VS = std::vector; using mypair = std::pair; class Solution { public: VS topKFrequent(VS& vsWords, int k) { VS vsOut; std::priority_queue pq; std::unordered_map um; // for(const auto i : vsWords) //1 um[i]++; //um[key]=value; //um[i] = um[i]+1 for(const auto i:um){ //2 pq.push(make_pair(-i.second,i.first)); if (pq.size() > k) pq.pop(); } while(not pq.empty()){ //3 vsOut.push_back(pq.top().second); pq.pop(); } for(int i = 0; i < vsOut.size()/2; i++) //4 std::swap(vsOut[i], vsOut[vsOut.size()-i - 1]); return vsOut; } }; Menos

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Meraki

a detailed troubleshooting scenario for VPN was asked. a site-to-site VPN, user from one site cannot get to a resource on another site.

8 respuestas

Hello, Can anyone tell me the best link to study troubleshooting scenarios from?

#sh vlan brief

There was no one answer for this, and since I didn't know much about vpns, the interviewer guided me through the possible answers! Menos

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CSC

How does STP work...how does it know who will control everything?

5 respuestas

It disables redundant paths and only leaves one broadcast path in a mesh network. It then enables a previous blocked path if one of the primary links becomes disconnected. This creates a network that won't cause broadcast storms but still provide redundancy. Menos

STP operates at the Data Link layer of the OSI model which prevents traffic loops. STP chooses only one root switch/bridge, out of which all data paths span out logically getting the data to the target the quickest and detect and correct link failures when a switch/bridge fails...STP stands for Spanning Tree Protocol. The root is chosen based on its BID( Bridge ID) which is the combination of a 2 byte priority field and the bridge/switch MAC address....Since all switch/bridges on the network start out with the same priority, the one with the lowest MAC address becomes the root bridge. Menos

STP is basically used for loop prevention and to prodive redundancy. Devices participating in STP perform a root bridge election process. Device having the lowest priority will be choosen as the root bridge. If every device participating in STP have the same priority value, device with the lowest mac-address becomes the root bridge. The root bridge will be responsible to make th overall traffic flow decision on the LAN. Non-root bridges use a lowest cost path to reach the root bridge. This cost is dependent on the interface speed. Topological changes downstream from the root bridge is communicated to the root bridge. Menos

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Mindtree

Q: Vlans-- The interviewer asked me the following Scenario. a. Two Switches are connected. b. There are Two Vlans. Vlan 10 & Vlan 20. c. Vlan 10 IP: 192.168.1.0 /24 | Vlan 20: 192.168.2.0 /24 d. Users in Vlan 10 can communicate with users in Vlan20.

5 respuestas

My Response: I asked him a return query stating that is there any L3 Device as he mentioned the IP address. He answered No. I was confident that the Users in Vlan 10 will not able to communicate with Users in Vlan20 until and unless if there is a L3 device such as Router or a L3 Switch or multi layer Switch. I explained him the same but still he said that its communicating. He also informed that there are only Two Switches which are L2 Switches. 2. Another Question: What is you Favourite Routing Protocol? Answered: EIGRP. 3. What is FC condition? Ans: FD > AD (Feasible Condition > Advertising Distance). Instead of Saying Advertising Distance, I said Administrative Distance (which is 90 for EIGRP). 4. What are the Requirements for an EIGRP Router to form the Neighbors? Ans: Hello Packets | AS number should be same | K values must match. Mentioned Hold timers which is not a required. Cheers, Raja. Menos

Yes this is possible through inter-vlan routing. 1st need to take 2 MLS switch, connect them, create vlans and configure IP addresses for both vlan. Menos

Yes this is possible through inter-vlan routing. 1st need to take 2 MLS switch, connect them, create vlans and configure IP addresses for both vlan. Menos

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Meta

What's the maximum theoretical number of TCP connections a host may have open?

5 respuestas

I think it is 2^16*2^16 = 2^32. Even though the port number field is 16-bits, a connection is a pair of ports, that should result in 2^32. Menos

Hi Poster, May I know what other questions where asked during your interview? Anything would greatly help. My email is operationstealth@hotmail.com... Thanks! Menos

Agree with KK , a connection is a pair of s.port and d.port - Hence total TCP connections possible are 2^32 on each host. Menos

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CMS Info Systems

What port is used for FTP?

4 respuestas

Port 21

both 20 and 21

20 and 21

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Meta

Coding questions are from Med-Hard LC Networking - BGP/OSPF/Redundancy, STP, IPv6

4 respuestas

The key in these questions is to cover the fundamentals, and be ready for the back-and-forth with the interviewer. Might be worth doing a mock interview with one of the Facebook or ex-Facebook Network Engineer experts on Prepfully? They give real-world practice and guidance, which is pretty helpful. prepfully.com/practice-interviews Menos

Can you share some details around system design ? Was it realted to bringing up a new data center or discussion about your previous projects ? Menos

Practice 50-100 LC Easy to Med questions. Should put you on the track to success. Networking - Read CCNP guides for OSPF and BGP. Expect questions in depth and very specific. Menos

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