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Epic
A un Project Manager/Implementation Consultant le preguntaron...18 de marzo de 2011

You have a bouquet of flowers. All but two are roses, all but two are daisies, and all but two are tulips. How many flowers do you have?

39 respuestas

The solution is quite simple, if you start with the “All but 2” first: Roses = All but 2 = Two flowers are not a rose; one tulip, one daisy Daisies = All but 2 = Two flowers are not a daisy; one rose, one tulip Tulips = All but 2 = Two flowers are not a tulip; one rose, one daisy Answer: One rose, one daisy, one tulip. Menos

3 flowers - 1 rose, 1 daisy and 1 tulip

I would say, "Do you consider three flowers to be a bouquet?"

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American Heart Association

What's the color of money???....

29 respuestas

An 80's movie about Pool hustlers staring Paul Newman and Tom Cruise.

(Well played, Chad.) (Well played, Chad...)

its rainbow color; when you have it, it shows your colors to others around you; when you don't, it shows colors of others around you. Menos

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UnitedHealth Group

Pepsi or coke?

28 respuestas

Water!

Coke, please. And a bourbon chaser to go with it. Thanks. ;>)

Personally, I can't tell the difference between Coke and Pepsi and I try to limit my consumption of soft drinks because they are unhealthy. If you compare the ingredients in in a can of Coke vs. a can of Pepsi, they are essentially the same, but everybody has their particular brand affiliation. That's really where these beverage producers excel: branding. And I think UnitedHealth could learn a lot from Coke and Pepsi in terms of branding and PR. The insurance industry in general isn't always seen in the best light and I think that's something I could really help with, marketing UnitedHealth's services so that customers have the same positive feelings they do towards Coke and Pepsi. Menos

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Epic

An apple costs 20 cents, an orange costs 40 cents and a grapefruit costs 60 cents, how much is a pear?

23 respuestas

I would say a "pair" of apples cost 40 cents, a "pair" of oranges cost 80 cents, and a "pair" of grapefruit cost 120 cents. Menos

This question is meant to be asked verbally so what you hear is Pear but what they mean is PAIR. So the issue is can you think beyond past paterns or are you predisposed to thinking linearly. Oh yeah... a pair is 2. Menos

your numbers are off a bit..its apple = 40 orange = 60 grapefruit = 80..the answer is 40 cents because its 20 cents per vowel in the word...tricky but right... Menos

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Aguettant

Quelles sont les valeurs de l'entreprise?

21 respuestas

Bởi vì tôi ưu thích công việc này

Tôi cảm thấy rất yêu thích công việc này

Công việc này là niềm mơ ước của tôi

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Google

you are on a biz trip and travelling from one city to another. you have a stack of unsorted flight boarding passes. only departure city and destination city are on the boarding pass. how do you find the first departure city and your final destination city

15 respuestas

Your current location is your departure city. Your final destination is the city whose name occurs only once among all the city names minus your departure city. Menos

Why wouldn't you just look at all of the cities listed on the documents and the two which don't ever repeat are your departure and destination city. (For the two that don't repeat, one will only be listed as a departure and the other one will be the one that is only listed as a destination.) Menos

Assume this is a acyclic graph (a city is not visited again once you leave it). Now, arrange the boarding passes and note the number of times a city appears in departure as well as arrival. For all intermediate cities this number will be the same. For the initial city the arrival-departure = -1 and for the destination arrival-departure = +1. Now, you start traversing from there. Form a table where you take each node and note the next node. For cyclic graphs it is more complex. You will still find the initial and destination city the same way but the traversal will be hard. Menos

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Amazon

The manager of component 'A' says his functionality is more important than that of component 'B.' The manager of component 'B' says his is more important than that of component 'A.' You can only implement one A or B, but not both - which do you choose to implement.

14 respuestas

The key question to ask is definition of "IMPORTANT". Is it important to the managers (ego equation), important to the end consumer or important for Amazon. The first one needs to be thrown out immediately and the others must be quantified based on achievability, impact on end user and ROI. Menos

I would say whichever is more valuable to customer & gives competitive advantage to Amazon. Menos

In addition to the above suggestions, I would look at cost and time to market and then score both options. Then define value metrics. The cheapest and most valuable either as a technology sustainer or for customer wins. Given that it's Amazon, customer value will hold up the highest as one of their corporate culture virtues. Menos

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Google

What is the marginal cost of a gigabyte in gmail?

12 respuestas

Here's my guess at what they're looking for. Marginal cost - this is the additional cost for adding a user. It doesn't need to take in to account the software development effort, but it should take out the atomized cost for everything else. You need to price out the the cost of the enterprise HD/GB. We can call it $1 by GB. Then you need to realize that there needs to be redundancy, so at the lest we need to double that number, if they put a super high value on data retention triple it. Then you need to think about server cost and divide that out, server rack space cost and physical rack area...etc. So if it's $1 for the actual HD space it's probably more like $2.50-$3.50 for the total marginal cost. I don't work for google, but my guess is that they're looking at the though process. What will change with a marginal user increase and what will not. If you only think of the cost of the HD then you're not getting a job with google. Menos

The marginal cost of adding a gigabyte is either zero or thousands of dollars.. Either the gigabyte is already physically in existence or you would have to build a new server. The marginal cost is not averaged across all gigabytes. There might be a minor increase in energy consumption due to this extra gigabyte, but who will notice that? If your goal is to stand out in an interview, I would suggest going the Thousands of Dollars answer. For those non computer guys out there, let's relate this question to something physical.. What is the marginal cost of adding one more person to an airline flight.. Their are two situations, the plane in not already full so we can essentially neglect the cost of the additional passenger since it is so low.. (The extra energy to move the 200 pounds, when the plane is already moving hundreds of thousands of pounds, and the 25 cents for a soda..) But if the plane is already full, then the marginal cost of one extra passenger is the cost to fly a second plane.. Thousands of dollars... Menos

Isn't marginal cost the cost to produce an additional unit? So costs like designing the user interface, maintaining the webpage (which would have to be done no matter the gigabyte capacity) shouldn't be accounted for. Menos

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Epic

How many minutes before 5pm is it if 30 mins ago it was four times as many minutes after 3pm?

11 respuestas

The answer is 18 minutes. It made sense to me to sketch a timeline showing the 3 components of time given in the problem that add up to the 120 minute total span. (X = minutes before 5pm, 30 min gap, and 4X is time between 3pm and the start of the 30 min gap.) Visually and chronologically it would look something like: 3pm --> 4X --> 30 min --> X --> 5pm. So then algebraically, the equation is 4X + 30 min + X = 120 min. Therefore 5X = 90 or X = 18. Menos

18 mins before 5 = 4:42. 30 before 4:42 puts the time at 4:12. There are 72 minutes between 3 and 4:42 divided by 4 is 18. So the answer is 18 mins before 5pm. Menos

That last explanation seems like you need to know the answer before you even start trying to solve. My solution is as follows: 30 minutes before 5 is 4:30 leaving 90 minutes between 3 and then. The remaining time needs to be split into an interval so that x4 exists. The most logical interval would be in 5ths because the 4 proceeding intervals would be 4x greater then the following. 90/5=18 for each interval. 18 being four times less then 72 minutes proceeding it. This literally look me about a minute and a half to reason through, which I'm assuming the interviewer would not want to sit through. Guess I would fail. Menos

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Google

What's the probability of pulling four of a kind from a deck of cards in five tries.

10 respuestas

It has been a long time since I last studied this, so I would welcome any corrections. I think Shrenik's last paragraph isn't totally accurate. I think the answer is: 1 - (1 - 3/51 * 2/50 * 1/49)^5 While Shrenik is right that the odds at each attempt are independent of the previous attempt, the overall odds do improve if you know in advance there will be many attempts. An easier example to explain is: what are the odds that you will get a '6' at least once when tossing a die 5 times. The answer is NOT 1/6. The answer is also not 5/6. It's one minus the chance that in 5 consecutive attempts you will NOT get a '6': 1 - ( 1 - 1/6 )^5. The more attempts you know you'll have, the closer you get to 1, but you're never 100% guaranteed. Menos

Here's how Im thinking about it- Since you are given 5 tries, any of the following possibilities counts as success: 1) 1,2,3,4 are the same, 5 is different. Probability = 1*(3/51)*(2/50)*(1*49) 2) 1,3,4,5 are the same, 2 is different Probability = 1*(48/51)*(3/50)*(2/49)*(1/48) 3) 1,2, 4,5 are the same, 3 is different Probability = 1*(3/51)*(48/50)*(2/49)*(3/48) 4) 1,2,3,5 are the same, 4 is different Probability = 1*(3/51)*(2/50)*(48/49)*(1/48) 5.) 2,3,4,5 are the same, 1 is different Probability = 1*1*(3/50)*(2/49)*(1/48) The final probability is the same of all these individual probabilites. Menos

The answer is 0.0240%, which is the probability of drawing "4 of a kind" in 5-card poker. See: http://en.wikipedia.org/wiki/Poker_probability Menos

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