## Pregunta de entrevista

Entrevista de Field Engineer

-Minneapolis, MN

# If water in a well rises 2 feet each day and falls 1 foot each night, how long til the water reaches the top of a 10 foot well

Respuesta

## Respuestas de entrevistas

9 respuestas

1

It will reach the top on the 9th day, the question only asks about reaching the top and not remaining at a 10 foot level. The level will be 8 ft at the end of 8th day and then it will go up to 10ft the next day; day 9.

AmaKay en

1

every day it rises 2 feet during the day and one feet at night it drops basically it rises only 1 foot each day and shall take 10 days to get to 10 feet.

10 days en

0

net gain per day of 1 ft, with a peak gain of 2 ft. If day=12 hrs and night = 12 hrs, then the peak on day 9 will reach the 10 ft mark, or 8.5 days

Anónimo en

0

Means you best have mop and bucket by days end of the 8th day

Anónimo en

0

It doesn't matter because I'z aint fetching the water for Ms. Sally. Today is insurrection.

Anónimo en

3

on the 9th day

Anónimo en

1

2*X-1*X=10 then X=10 X= days passed

Ehsan en

0

The question is missing boundary conditions. What level did the water start at? What time of year is it (how many hours in the day vs night)? What is the flow rate between the maxima and minima? You can't really answer it until you know those.

Anonymous en

0

2*X-1*X=10 then X=10 X= days passed

Ehsan en